Age Problems - Civil Service Exam

Introduction to Age Problems

Age problems are common in math and often appear in exams like the civil service exam. These problems involve relationships between ages of people at different points in time and usually require forming equations to find the unknown ages.

Common Clues in Age Problems:

  1. Current Age: The present age of a person.
  2. Past Age: The age of a person at a certain time in the past.
  3. Future Age: The age of a person at a certain time in the future.
  4. Relationships: Age differences, sum of ages, or multiples of ages.

Basic Approach to Solving Age Problems:

  1. Define Variables: Assign variables to represent the unknown ages. For example, let xx be the current age of a person.

  2. Set Up Equations: Use the information given to set up an equation or equations. Key phrases often used are:

    • “Years ago” indicates subtraction.
    • “Years from now” indicates addition.
    • “Twice as old,” “half as old,” etc., indicates multiplication or division.
  3. Solve the Equations: Combine the equations, if necessary, to find the unknown values.

  4. Check the Answer: Substitute your solution back into the problem to ensure it fits all conditions.

Example Problem:

Problem:
Anna is twice as old as her brother Mark. In 5 years, the sum of their ages will be 35. How old are they now?

Solution:

  1. Define variables:
    Let xx be Mark’s current age.
    Then, Anna’s current age is 2x2x.

  2. Set up the equation based on the future scenario:
    In 5 years, Mark’s age will be x+5x + 5 and Anna’s age will be 2x+52x + 5.

  3. Use the sum of their future ages:

    (x+5)+(2x+5)=35(x + 5) + (2x + 5) = 35
  4. Simplify and solve:

    3x+10=353x=25x=8.333x + 10 = 35 3x = 25 x = 8.33

Since ages must be whole numbers, check if rounding fits the condition or interpret the context.

Key Tips:

  • Read carefully to identify the current, past, or future context.
  • Express all ages in terms of the same variable.
  • Check each solution step to ensure it logically follows from the previous information.

More Sample Problems

Problem One:

Jessica is twice as old as her daughter Carla. Four years ago, the sum of their ages was 28. How old is Jessica now?

Choices:

A) 24 years

B) 28 years

C) 32 years

D) 36 years

Answer: C) 32 years

Solution:

  1. Let Carla’s current age be .
  2. Jessica’s current age is then because she is twice as old as Carla.
  3. Four years ago, Carla’s age was X and Jessica’s was 2X.
  4. The sum of their ages four years ago was 28, so:
  5. Simplifying, we get:
  6. Solving for 𝑐, we add 8 to both sides:
  7. Then, divide by 3:
    X
  8. Jessica’s current age is .

Jessica is currently 32 years old.

Problem Two:

Robert is four times as old as his son Daniel. Five years ago, the sum of their ages was 50. How old is Robert now?

Choices:

A) 40 years

B) 44 years

C) 48 years

D) 52 years

Answer: C) 48 years

Solution:

  1. Let Daniel’s current age be X.
  2. Robert’s current age is .
  3. Five years ago, Daniel’s age was X and Robert’s was .
  4. The sum of their ages five years ago was 50, so:
  5. Simplifying, we get:
  6. Solving for 𝑑, add 10 to both sides:
  7. Then, divide by 5:
    X
  8. Robert’s current age is .

Robert is currently 48 years old.

Problem Three:

Anna is four times as old as her daughter Beth. Three years ago, she was five times as old as Beth. How old is Anna now?

Choices:

A) 28 years

B) 32 years

C) 36 years

D) 48 years

Answer: D) 48 years

Solution:

  1. Let Beth’s current age be X.
  2. Anna’s current age is because she is four times as old as Beth.
  3. Three years ago, Beth’s age was X and Anna’s was .
  4. At that time, Anna was five times as old as Beth, so:
  5. Expanding and simplifying the equation:
  6. Rearranging to solve for :
  7. Dividing both sides by -1:
    X
  8. Anna’s current age is

 

Age Problem Exercises

1. Lucas is twice as old as Elena. Seven years ago, the sum of their ages was 34. How old is Lucas now?

2. Mia is two years younger than Dax. Six years ago, the sum of their ages was 32. How old is Dax now?

3. David is six times older than Nancy. In five years, the sum of their ages will be 87. How old is Nancy now?

4. Henry is four times older than Lisa. Ten years ago, the sum of their ages was 50. How old is Henry now?

5. Samantha is five times older than Grace. In 12 years, the difference in their ages will be 44. How old is Grace now?

6. Mark is twice as old as Rachel. Seven years ago, the sum of their ages was 34. How old is Mark now?

7. Sophia is three times older than Emma. In eight years, the sum of their ages will be 88. How old is Emma now?

8. Andrew is six years older than Kevin. Four years ago, the sum of their ages was 56. How old is Kevin now?

9. Linda is four times older than her brother Sam. In eight years, Linda will be three times older than Sam. How old is Linda now?

10. Peter is three times as old as his sister Maria. In ten years, Peter will be twice as old as Maria. How old is Maria now?

Answers

1. Luca’s age is 32

2. Dax = 23 years old

3.  Nancy = 11 years old

4. Henry’s age is 56

5. Grace is 11 years old

6. Mark’s age is 32

7. Emma’s age is 18

8. Kevin’s age is 29

9. Linda’s age is 64

10. Maria’s age is 10.