Percentage Problems - Civil Service Exam

Overview of Solving Percentage Composition Problems

Percentage composition problems are a type of mathematical question where you calculate the proportion of a specific component within a mixture or total, expressed as a percentage. These problems often arise in chemistry, cooking, finance, and other practical fields.

Step-by-Step Guide to Solve Percentage Composition Problems

  1. Identify the Components: Begin by determining the mass, volume, or quantity of each component in the mixture as well as the total mass, volume, or quantity of the mixture.

  2. Write Down the Formula: The basic formula for finding the percentage of a component in a mixture is:

    Percentage=(Part/Total) × 100% 
  3.  
    Part: This is the quantity of the component for which you are calculating the percentage.
  4.  
    • Total: This is the total quantity of all components in the mixture.
  5. Substitute the Values: Replace “Part” and “Total” in the formula with the respective values identified in step 1.

  6. Perform the Calculation: Execute the division followed by multiplication by 100 to convert the fraction into a percentage.

  7. Interpret the Result: The result is the percentage that the specific component contributes to the overall mixture, reflecting its proportionate share.

Example Problem and Solution

Problem: A salad mix contains 300 grams of lettuce, 100 grams of tomatoes, and 50 grams of carrots. Calculate the percentage of tomatoes in the salad mix.

Solution:

  • Total mass of the salad mix: 300 grams + 100 grams + 50 grams = 450 grams
  • Mass of tomatoes: 100 grams
  • Percentage of tomatoes:
    Percentage of tomatoes=(100 grams/450 grams) × 100% ≈ 22.22% Thus, tomatoes make up about 22.22% of the salad mix.

Common Mistakes to Avoid

  • Ignoring or Misidentifying Components: Ensure all components of the mixture are accounted for in the total.
  • Unit Mismatch: Ensure that all measurements are in the same units (e.g., all in grams or all in liters) before performing calculations.
  • Calculation Errors: Double-check calculations, especially the order of operations in the percentage formula.

 

Practice Test on Percentage Problems - Civil Service Exam

Question 1

Question:
A mixture of copper and tin consists of 18 kg of copper and 2 kg of tin. What percent of the mixture, by mass, is tin?

  • Choice A: 10%
  • Choice B: 11%
  • Choice C: 9%
  • Choice D: 12%
  • Answer: A
  • Solution:
    Total mass of the mixture = 18 kg + 2 kg = 20 kg.
    Percent of tin = 2 kg/20 kg × 100% = 10% 

Question 2

Question:
A certain blend of spices contains 4 kg of turmeric and 1 kg of pepper. What percent of the blend, by mass, is pepper?

  • Choice A: 20%
  • Choice B: 25%
  • Choice C: 15%
  • Choice D: 30%
  • Answer: A
  • Solution:
    Total mass of the blend = 4 kg + 1 kg = 5 kg.
    Percent of pepper = 1 kg/5 kg × 100% = 20% 

Question 3

Question:
A bag contains 30 kg of rice and 10 kg of beans. What percent of the bag’s contents, by mass, is beans?

  • Choice A: 25%
  • Choice B: 33%
  • Choice C: 20%
  • Choice D: 30%
  • Answer: A
  • Solution:
    Total mass of the contents = 30 kg + 10 kg = 40 kg.
    Percent of beans = 10 kg/40 kg × 100% = 25% 

Question 4

Question:
A canister of mixed nuts contains 16 kg of almonds and 4 kg of walnuts. What percent of the canister, by mass, is walnuts?

  • Choice A: 15%
  • Choice B: 20%
  • Choice C: 25%
  • Choice D: 30%
  • Answer: B
  • Solution:
    Total mass of the mixture = 16 kg + 4 kg = 20 kg.
    Percent of walnuts = 4 kg/20 kg × 100% = 20% 

Question 5

Question:
A container holds 28 liters of a solution composed of water and glycerin. If the glycerin accounts for 7 liters, what percent of the solution, by volume, is glycerin?

  • Choice A: 20%
  • Choice B: 25%
  • Choice C: 30%
  • Choice D: 35%
  • Answer: B
  • Solution:
    Total volume of the solution = 28 liters.
    Percent of glycerin = 7 liters/28 liters × 100% = 25% 

6. If x is 150% of y, then y is what percent of x+y

  1. 40%
  2. 20%
  3. 50%
  4. 75%

Solution:  x = 1.5y.  y=n(x + y).

y=p(1.5y + y)

y=p(2.5y)

y/2.5y = p

1/2.5 = p

.4 = p

40% = p